ref: 79412493b4cd9c428b6335613d9f720b79b3faf8
parent: d5999e4023f08294856780febf26edcb4f1cb37f
author: Roberto E. Vargas Caballero <[email protected]>
date: Wed Jan 20 10:51:03 EST 2016
Fix eqtype() Eqtype was not checking that both types had the same op, and it meant that pointer and array could be compared equal.
--- a/cc1/types.c
+++ b/cc1/types.c
@@ -521,9 +521,11 @@
return 0;
if (tp1 == tp2)
return 1;
+ if (tp1->op != tp2->op)
+ return 0;
switch (tp1->op) {
case ARY:
- if (tp1->op != tp2->op || tp1->n.elem != tp2->n.elem)
+ if (tp1->n.elem != tp2->n.elem)
return 0;
case PTR:
return eqtype(tp1->type, tp2->type);
@@ -530,7 +532,7 @@
case UNION:
case STRUCT:
case FTN:
- if (tp1->op != tp2->op || tp1->n.elem != tp2->n.elem)
+ if (tp1->n.elem != tp2->n.elem)
return 0;
p1 = tp1->p.pars, p2 = tp2->p.pars;
for (n = tp1->n.elem; n > 0; --n) {