ref: 01dc1e2c37938eea4226ac299dc518bfab6ef0c0
dir: /libmemdraw/defont.c/
#include <u.h> #include <libc.h> #include <draw.h> #include <memdraw.h> Memsubfont* getmemdefont(void) { char *hdr, *p; int n; Fontchar *fc; Memsubfont *f; int ld; Rectangle r; Memdata *md; Memimage *i; /* * make sure data is word-aligned. this is true with Plan 9 compilers * but not in general. the byte order is right because the data is * declared as char*, not ulong*. */ p = (char*)defontdata; n = (uintptr)p & 3; if(n != 0){ memmove(p+(4-n), p, sizeofdefont-n); p += 4-n; } ld = atoi(p+0*12); r.min.x = atoi(p+1*12); r.min.y = atoi(p+2*12); r.max.x = atoi(p+3*12); r.max.y = atoi(p+4*12); md = mallocz(sizeof(Memdata), 1); if(md == nil) return nil; p += 5*12; md->base = nil; /* so freememimage doesn't free p */ md->bdata = (uchar*)p; /* ick */ md->ref = 1; md->allocd = 1; /* so freememimage does free md */ i = allocmemimaged(r, drawld2chan[ld], md); if(i == nil){ free(md); return nil; } hdr = p+Dy(r)*i->width*sizeof(ulong); n = atoi(hdr); p = hdr+3*12; fc = malloc(sizeof(Fontchar)*(n+1)); if(fc == 0){ freememimage(i); return 0; } _unpackinfo(fc, (uchar*)p, n); f = allocmemsubfont("*default*", n, atoi(hdr+12), atoi(hdr+24), fc, i); if(f == 0){ freememimage(i); free(fc); return 0; } return f; }